$FE00 0000 > extract bits ABD AAAAAA BBBB DDDD ooooo
extension before normal instruction:
$7180 > extract bits AA BB CCCCC DD
About the last one.
AA are the extended bits for operand a.
and BB are the extended bits for operand b.
and we get a new operand: C.
in AA or BB
Data become 4 banks (default D0..7 and 3 new E0..23)
and Address : lsb switch A0..7 and B0..7(if lsb=1)
So does the other bit of Address
when <ea> is present
switches <ea> to <vea> (for $7100, line7 unused moveq)
like the lineF does?
I am thinking how a debugger would interpret it.